Searched refs:leap_days (Results 1 – 1 of 1) sorted by relevance
421 int month_, year, leap_days; in my_timegm() local439 leap_days = year - (tm->tm_mon <= 1); in my_timegm()440 leap_days = ((leap_days / 4) - (leap_days / 100) + (leap_days / 400) in my_timegm()444 + leap_days + month_days_cumulative [month_] + tm->tm_mday - 1) * 24 in my_timegm()